3(2x^2+5)=0

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Solution for 3(2x^2+5)=0 equation:



3(2x^2+5)=0
We multiply parentheses
6x^2+15=0
a = 6; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·6·15
Δ = -360
Delta is less than zero, so there is no solution for the equation

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